how can I subtract each element by one to generate a list contains all zeros i tried to solve it in recursive way

if I have a list how can I subtract each element by one in a recursive way ??I implemented this code

list=[5,4,3,2,1,1]
level=numbers[0]

def list_arrays(numb):
    if len(numbers)-1 < level:
      print("nograph")
   else:
     for i in range(len(numbers)):
       numbers[i] = numbers[i] - 1
         print(numbers)

the output should be like this

> [4,3,2,1,0,0]
> [3,2,1,0,0,0]
> [2,1,0,0,0,0]
> [1,0,0,0,0,0]

but its printed only the first array

> [4,3,2,1,0,0]

>Solution :

import numpy as np

l=[5,4,3,2,1,1]
arr = np.array(l)

# loop until all elements are 0
while not np.all((arr == 0)):
    for i in range(len(arr)):
        # subtract non-zero element by 1
        if not arr[i] == 0:
            arr[i] -= 1 
    print(arr)

output:

> [4 3 2 1 0 0] 
> [3 2 1 0 0 0] 
> [2 1 0 0 0 0] 
> [1 0 0 0 0 0] 
> [0 0 0 0 0 0]