txt file
Zurich, Sun, (8, 52)
Auckland, Sun, (20, 52)
Barcelona, Sun, (8, 52)
Vancouver, Sun, (0, 52)
Beirut, Sun, (9, 52)
Athens, Sun, (9, 52)
Amsterdam, Sun, (8, 520)
Toronto, Sun, (2, 52)
Vienna, Sun, (8, 52)
Winnipeg, Sun, (1, 52)
Atlanta, Sun, (2, 52)
Anchorage, Sat, (23, 52)
Warsaw, Sun, (8, 52)
Ankara, Sun, (10, 52)
Washington DC, Sun, (2, 52)
code:
list_aldskjfa = []
data = open('city_time.txt', 'r')
data = data.read()
list1 = []
for line in sorted(open('A1_cities_and_time.txt')):
list1.append(line)
print(line, end='')
print(list1)
output: ['Amsterdam, Sun, (8, 520)\n', 'Anchorage, Sat, (23, 52)\n', 'Ankara, Sun, (10, 52)\n', 'Athens, Sun, (9, 52)\n', 'Atlanta, Sun, (2, 52)\n', 'Auckland, Sun, (20, 52)\n', 'Barcelona, Sun, (8, 52)\n', 'Beirut, Sun, (9, 52)\n', 'Toronto, Sun, (2, 52)\n', 'Vancouver, Sun, (0, 52)\n', 'Vienna, Sun, (8, 52)\n', 'Warsaw, Sun, (8, 52)\n', 'Washington DC, Sun, (2, 52)', 'Winnipeg, Sun, (1, 52)\n', 'Zurich, Sun, (8, 52)\n']
As you can see, the list is alphabetized properly, with amsterdam, then anchorage, then ankara, etc. The problem is that the entire thing is a string – including the tuple and the date. The ideal output would look like [(‘Amsterdam’, ‘Sun’, (8,520)), (‘Anchorage’, ‘Sun’, (8,520)), etc.]
>Solution :
It seems as though what you need to do is split each entry of the list into a tuple. One nice solution is to use the parse module. Here’s a way to do it from scratch.
def sep(line):
line = line.strip()
parts = line.split(',')
a = int(parts[2][2:])
b = int(parts[3][1:-1])
return (parts[0],parts[1][1:],a,b)
output = list(map(sep,list1))