How do I get the unix timestamp as a variable in C++?

I am trying to make an accurate program that tells you the time, but I can’t get the current Unix timestamp. Is there any way I can get the timestamp?

I tried using int time = std::chrono::steady_clock::now(); but that gives me an error, saying that ‘std::chrono’ has not been declared. By the way, I’m new to C++

Let me know if you have the answer.

>Solution :

Try using std::time, it should be available in Dev C++ 5.11, but let me know if it also throws an error:

#include <iostream>
#include <ctime>
#include <cstddef> // Include the NULL macro

int main() {
    // Get the current time in seconds
    time_t now = std::time(NULL);

    // Convert the Unix timestamp to a tm struct
    tm *time = std::localtime(&now);

    // Print the current time and date
    std::cout << "The current time and date is " << time->tm_year + 1900
              << "-" << time->tm_mon + 1 << "-" << time->tm_mday
              << " " << time->tm_hour << ":" << time->tm_min
              << ":" << time->tm_sec << std::endl;

    return 0;
}

In this example, the std::time() function is called with a NULL argument to get the current time in seconds. The value returned by the std::time() function is then printed to the console using the std::cout object.

You can use the std::localtime() function to convert the Unix timestamp to a more human-readable format. This function returns a tm struct that contains the local time broken down into its component parts (year, month, day, hour, minute, etc.).