How do I pass a non-awaitable action to a method that takes a Func<Task>?

Suppose I have a method as follows…

public static async Task DoIt(Func<Task> doit) {
  // Do something first
  await doit();
  // Do something last
}

I can pass in an awaitable function as follows…

await DoIt(() => Task.Delay(1000));

If I want to pass in something non-awaitable, I can do it like this…

_ = DoIt(() => Task.Run(() => Console.WriteLine("Hi")));

…but this seems quite ugly. Is there a neater way of doing this?

>Solution :

If the action is an async, non-awaitable method (e.g. async void) there isn’t really a proper way to return a task. There is no way to return a task that signals its completion when the async void method finishes.

If the action is a synchronous method, you can just return Task.CompletedTask.

_ = DoIt(() => { Console.WriteLine("Hi"); return Task.CompletedTask; } );