how do i print out the avarage of several arrays with float?

i’m just starting with getting to know C, and i’m now following the cs50 course. i have a question on the following code.

I want to calculate the avarage score of the user input.

#include <cs50.h>
#include <stdio.h>

int main(void)
{

    int s = get_int("how many scores? ");
    int sum = 0;
    int score[s];
    
    for(int i = 0; i < s; i++)
        {
            score[i] = get_int("score: ");
            sum =  sum + score[i];
        }
    float avg = sum / s;
    printf("avarage: %f\n", avg);
}

So, it prints the avarage, but gets round down to .0000.
Is it because i am using a int to divide by? i have tried several things, like changing int to float, but without result.
How do I solve this?

>Solution :

This is an integer division:

float avg = sum / s;

Which means that 3 / 2 will be 1 (the decimal part is discarded). This will then be stored in avg as 1.f.

You need to make it into a floating point division. You can cast one of the operands to the desired type:

float avg = (float)sum / s;

Now both operands (sum and s) will be converted to float before the actual division takes place and the correct result will be shown, which is 1.5 + some zeroes in the example above.