-9223372036854775808 is the most negative int64_t. the problem is that if I use -9223372036854775808L or -9223372036854775808LL then I get the warning "integer literal is too large to be represented in a signed integer type, interpreting as unsigned". The issue is that the - is being treated separately and positive 9223372036854775808 is indeed too big for int64_t. If I try -9223372036854775808UL then I get the warning "unary minus operator applied to unsigned type, result still unsigned". How do I properly encode this number?
>Solution :
The issue you’re facing is due to the fact that the literal -9223372036854775808 is being treated as a positive number because it’s outside the range of a signed 64-bit integer. To properly represent this number in your code, you can use the LL suffix to indicate a long long integer, and also use the unary minus operator to make it negative. Here’s an example:
#include <stdint.h>
#include<iostream>
using namespace std;
int main() {
int64_t myInt = -9223372036854775807LL - 1LL;
cout<<myInt; // prints -9223372036854775808
return 0;
}
By subtracting 1 from -9223372036854775807LL, you effectively obtain the minimum representable value of int64_t. The use of LL ensures that the literal is treated as a long long integer. This approach avoids the issues with interpretation as an unsigned type or exceeding the range of signed integers.