How do you move n characters that are between 2 words to the end of the line (inside of a multi-line string)?

The multi-line string always contains XY, followed by a few characters (not always the same amount of characters), followed by :thiSWORD:

The goal is to move these few characters that are in the middle to the end of the line

So, for example, this is the original string:

XY1239:thiSWORD:a6b4ba21ba54f6bde411930b0d88432f
XY545:thiSWORD:b598944d1ba4c787e411800b8043559c
XY4239:thiSWORD:a6b4ba21ba54f6bde411930b0d8817c6

In the end it would look like this:

XY:thiSWORD:a6b4ba21ba54f6bde411930b0d88432f1239
XY:thiSWORD:b598944d1ba4c787e411800b8043559c545
XY:thiSWORD:a6b4ba21ba54f6bde411930b0d8817c64239

I have tried something along the lines of

str.replace(/(\w{4})(\w{48})/g, '$2$1');

But that only moved 4 characters, so lines that had 3 or 5 characters between XY and :thiSWORD: were messed up.

>Solution :

You can use 2 capture groups, and use those in the replacement:

XY(\d+)(.*)

• XY Match literally
• (\d+) Capture 1+ digits in group 1
• (.*) Capture the rest of the line in group 2

See a regex demo.

[
  "XY1239:thiSWORD:a6b4ba21ba54f6bde411930b0d88432f",
  "XY545:thiSWORD:b598944d1ba4c787e411800b8043559c",
  "XY4239:thiSWORD:a6b4ba21ba54f6bde411930b0d8817c6"
].forEach(s => {
  console.log(s.replace(/XY(\d+)(.*)/, "XY$2$1"))

})

Another variant using 1 or more word characters \w+ if there can also be word characters instead of only digits, matching 32 word chars instead of 48, word boundaries on the left and right and matching :thiSWORD:

\bXY(\w+)(:thiSWORD:\w{32})\b

Regex demo