How store address of an array[] in a variable

This seems like a silly question. I have an array of chars and want to store the address of the array in another variable, but can’t seem to declare the correct type for the array address (I’m using gcc):

IN:

int main(void){
  char cha[] = "abcde";
  char **arrayAddress = &cha;
}

OUT:

arrayaddress.c: In function ‘main’:
arrayaddress.c:3:25: warning: initialization of ‘char **’ from incompatible pointer type ‘char (*)[6]’ [-Wincompatible-pointer-types]
    3 |   char **arrayAddress = &cha;
      |                         ^

This is expected, I have read elsewhere that the type of cha should be char(*)[6]. But when I try to declare arrayAddress with this type, my program fails:

IN:

int main(void){
  char cha[] = "abcde";
  char (*)[6]arrayAddress = &cha;
}

OUT:

arrayaddress.c: In function ‘main’:
arrayaddress.c:3:10: error: expected identifier or ‘(’ before ‘)’ token
    3 |   char (*)[6]arrayAddress = &cha;
      |          ^
make: *** [<builtin>: arrayaddress] Error 1
       ^

How do I define arrayAddress correctly?

>Solution :

It is written:

char (*arrayAddress)[6] = &cha;

Notice that the name of variable gets tucked in middle of the expression.