how to access c 2d array with 1 index

I have the following:

#include <stdio.h>

int main() {

    int a[2][2] = { 0,1,2,3};
    printf("\n%d %d \n%d %d\n",a[0][0],a[0][1],a[1][0],a[1][1]);
    printf("%d %d %d %d\n",*a[0],*a[1],*a[2],*a[3]);

    return 0;
}

which returns:

0 1 
2 3
0 2 0 1491303602

Is there a way to access the 2d array with 1 index? Since the array is held in contiguous memory, shouldn’t we be able to do this?

also:

printf("\n%d %d \n%d %d\n",&a[0][0],&a[0][1],&a[1][0],&a[1][1]);
printf("%d %d %d %d\n",a[0],a[1],a[2],a[3]);

produces the following:

1137924528 1137924532 
1137924536 1137924540
1137924528 1137924536 1137924544 1137924552

so why are the memory addresses of the first two elements &a[0][0] = a[0]
and &a[0][1] = a[1] but the last two don’t match?

>Solution :

#include <stdio.h>

int main(void) {

    int a[2][2] = { 0,1,2,3};
    printf("\n%d %d %d %d\n",a[0][0],a[0][1],a[1][0],a[1][1]);
    printf("%d %d %d %d\n",*a[0],*(a[0] + 1), *a[1], *(a[1] + 1));
}

https://godbolt.org/z/3avvnssn5

Result:

0 1 2 3
0 1 2 3