How to call a bash script with arguments and then have the script call an AWK program with those arguments?

I have a bash script named run.sh which contains this:

#!/bin/bash

awk -f filter NAV.TXT

filter is this awk program:

BEGIN { FS = OFS = "\t" }
($1 == "PLT") && ($2 == "5") && ($3 == "US") && ($4 == "1") && ($2 == "5" || $2 == "7") { print; }

Unfortunately, everything is hardcoded in that program. I want to replace all those (hardcoded) strings with parameters and pass into the program values for the parameters.

I imagine calling run.sh something like this:

bash run.sh PLT 5 US 1 5 7

And then inside run.sh it calls the filter program, passing to it the arguments. The filter program then uses those passed-in values. How to do this?

>Solution :

awk accepts variable definitions with -v or as file arguments that look like var=value.

So you can rewrite filter as:

BEGIN { FS = OFS = "\t" }
($1 == arg1) && ($2 == arg2) && ($3 == arg3) && ($4 == arg4) && ($2 == arg5 || $2 == arg6) { print; }

then invoke awk as:

awk -v arg1=PLT -v arg2=5 -v arg3=US \
    -v arg4=1 -v arg5=5 -v arg6=7 \
    -f filter NAV.TXT

or

awk -f filter NAV.TXT \
    arg1=PLT arg2=5 arg3=US arg4=1 arg5=5 arg6=7