How to call a function from a function pointer?

August 17, 2022

How can you call a function from only a pointer to the function. For example, assuming the function has a return type of void:

void print()
{
    std::cout << "Hello World!" << std::endl;;
}

void run_func(void* func)
{
    func(); // what im trying to do (doesnt actually work)
}

int main()
{
    run_func(print);
}

Expected output:

Hello World!

It’s a bit like how std::thread creates a thread from the pointer of a variable.

>Solution :

void print()
{
    std::cout << "Hello World!" << std::endl;;
}

// Change your parameter as follows. You need to wrap function
// pointers in parantheses.
// void run_func(void *func())
void run_func(void (*func)())
{
    func(); // what im trying to do (and now works)
}

int main()
{
    run_func(print);
}