how to convert a normal list to 2d list + changing the values to integers

I want to convert a normal list to 2d list and want to change the numbers to integers instead of str
I have somthing like this

my_list = ['00000000', '00000000', '00111000', '00101000', '00101000', '00000000', '00000000', '00000000']

I want somthing like this using for loop:

my_list = [[00000000], [00000000], [00111000], [00101000], [00101000], [00000000], [00000000], [00000000]]

>Solution :

You may use a list comprehension here:

my_list = ['00000000', '00000000', '00111000', '00101000', '00101000', '00000000', '00000000', '00000000']
output = [[int(x)] for x in my_list]
print(output)  # [[0], [0], [111000], [101000], [101000], [0], [0], [0]]

Note that there is no Python integer literal 00000000, which is really the same as 0. If you need the leading zeroes, then you should leave your data as strings.

Edit:

To get a 2D list of single numbers from each string, use:

my_list = ['00000000', '00000000', '00111000', '00101000', '00101000', '00000000', '00000000', '00000000']
output = [[int(x) for x in list(y)] for y in my_list]
print(output)
# [[0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0],
#  [0, 0, 1, 1, 1, 0, 0, 0], ...