How to convert UTF-8 notation to python unicode notation

Using python3.8 I would like to convert unicode notation to python notation:

s = 'U+00A0'
result = s.lower() # output  'u+00a0'

I want to replace u+ with \u:

result = s.lower().replace('u+','\u') 

But I get the error:

SyntaxError: (unicode error) 'unicodeescape' codec can't decode bytes in position 0-1: truncated \uXXXX escape

How can I convert the notation U+00A0 to \u00a0 ?

EDIT:

The reason I wanted to get \u00a0 is to further use encode method to get b'\xc2\xa0'.

My question: given a string in the following notation U+00A0 I would like to convert it to byte code b'\xc2\xa0'

>Solution :

you are struggling with the representation of something versus its value…

import re
re.sub("u\+([0-9a-f]{4})",lambda m:chr(int(m.group(1),16)),s)

but for u+00a0 this becomes \xa0

but same with the literal \u00a0

s = "\u00a0"
print(repr(s))

once you have the proper value as a unicode string you can then encode it to utf8

s = "\xa0"
print(s.encode('utf8'))
# b'\xc2\xa0'

so just final answer here

import re
s = "u+00a0"
s2 = re.sub("u\+([0-9a-f]{4})",lambda m:chr(int(m.group(1),16)),s)
s_bytes = s2.encode('utf8') # b'\xc2\xa0'