how to count the total amount of digits in a byte[] if you were to sum the array

i want to make a function that counts the amount of digits once the value is sumed up

lets say i have this array

byte[] array = new byte[] { 200, 100, 200, 250, 150, 100, 200 };

once this is sumed up you’ll have a value of 1200

you can get the amount of digits with these functions

Math.Floor(Math.Log10(1200)+1) // 4

but if i sum it up and there are too many values in the array i get an integer overflow

public decimal countDigits(byte[] array)
{
    decimal count = array[0];

    for (int i = 1; i < array.Length; i++)
    {
         count = Math.Log10(Math.Pow(count, 10)+array[i]);
    }

    return count;
}

this does give the correct output i want but this causes a integeroverflow if the count is greater than 28.898879583742193 (log10(decimal.MaxValue))

>Solution :

There’s a BigInteger data type that can sum up arbitrary (integer) values. It even has a Log10 method, so it works very similar to a standard integer variable. The only limitation is that the result of BigInteger.Log10 must be smaller than Double.MaxValue, but that sounds like a reasonable limitation. (10^1E308=10^10^308 is a really huge number)