How to exclude the first 2 lines and only number list the rest of the file?

I’m trying to number list a certain section of the file but I’m not managing.

I want the IP section to be numbered only

Here is what I want to have:

Output of what I would like

Here is what I get:

Output of what I get

3. echo "Number Server"
   echo "——– ——–"
   sed -n ‘1,2s/^/ /’ server.list.txt
   tail -n +3 server.list.txt | nl
   echo -n "Enter the server number to delete: " select
   read select
   if [[ $select -eq 3 ]]
   then
   sed -i ‘3d’ server.list.txt #deletes the 3rd line
   elif [[ $select -eq 4 ]]
   then
   sed -i ‘4d’ server.list.txt #deletes the 4th line
   elif [[ $select -eq 5 ]]
   then
   sed -i ‘5d’ server.list.txt #deletes the 5th line
   else
   echo ""
   echo "ERROR: The number entered is invalid !!!"
   echo ""
   fi;;

The output shown below happens when the user enters the number ‘3’ on the menu

Edit: With some help, I was able to list the last 2 lines with numbers. Now I am trying to produce this output:

Number Server IP

1 127.0.0.1
2 192.168.40.30

>Solution :

Use sed to print the first two lines with spaces at the beginning.

Then use tail to pipe the rest of the file to nl.

sed -n '1,2s/^/   /' server.list.txt
tail -n +3 server.list.txt | nl