How to extract date from a column in Pandas?

I am trying to extract only dates from a column(Result) of a dataframe. Dates will only start from year 2000 and beyond but the format of date could be any including datetime.

What I want is just date.

Is there a simple way of doing it with some easy Regex codes ?

Example of dataset:

date_extract_df = pd.DataFrame({
'Result':[': XYZ',': 39 YRS/M',': Self',': HOME COLLECTION',': 10593974',
           ': 012408030006',': 03/08/2024',': 03/Aug/2024 11:50 AM',': 03/Aug/2024 03:24 PM',
            ' ','31.80','15'],
 'Unit':['dfd','dfdfd','tytyt','03/08/2024','fgf','tyt','xcx','ere','sds','03/Aug/2024 03:24 PM',
        '4545','5656']
})

Expected Result:

    0
    1
    2
    3
    4
    5
    6 03/08/2024
    7 03/Aug/2024
    8 03/Aug/2024
    9 03/Aug/2024
    10
    11

I am not good at Regex and have tried below code:

date_extract_df.Result.str.extract(r"^[0,1]?\d{1}\/(([0-2]?\d{1})|([3][0,1]{1}))\/(([1]{1}[9]{1}[9]{1}\d{1})|([2-9]{1}\d{3}))$")

Is there a way to figure out Rows containing dates in the column and then filter that row to extract date ?

I was trying this for a similar approach:

datetime.datetime.isoformat(date_check['Result'][9])

date_check['Result'].apply(lambda x: datetime.datetime.isoformat(x))

>Solution :

Minus the epoch time (line 6), this should do the task

pd.to_datetime(date_extract_df["Result"].str.replace(": ",""), errors="coerce")

To go deeper, you can use third-parties tools like dateparser to cover more cases