How to fill an array with a fixed value of datetime64 data type in NumPy?

I want to fill a numpy array with a fixed datetime64 value. The output should look something like this:

array(['2012-09-01', '2012-09-01', '2012-09-01', '2012-09-01',
       '2012-09-01'], dtype='datetime64[D]')

Where the shape of the array and the date value are variable.

Currently I am doing it this way:

shape = (5, )
date = "2012-09"

date_array = np.ones(shape=shape) * np.timedelta64(0, 'D') + np.datetime64(date)

I was wondering if there is a shorter and more readable way to get the same output?

>Solution :

Use numpy.full:

out = np.full(shape, np.datetime64(date))

# or
out = np.full(shape, date, dtype='datetime64[D]')

Or numpy.tile:

out = np.tile(np.array(date, dtype='datetime64[D]'), shape)

Or numpy.repeat and reshape:

out = np.repeat(np.array(date, dtype='datetime64[D]'),
                np.product(shape)).reshape(shape)

NB. for a single dimension np.repeat(np.array(date, dtype='datetime64[D]'), 5) is enough.

Output:

array(['2012-09-01', '2012-09-01', '2012-09-01', '2012-09-01',
       '2012-09-01'], dtype='datetime64[D]')