How to filter a list of strings?

I have a list of strings that contain Non-English/English words. I want to filter out only English words.

Example:

phrases = [
    "S/O अशोक कुमार, ब्लॉक न.-4डी, S/O Ashok Kumar, Block no.-4D.",
    "स्ट्रीट-15, विभाग 5. सिविक सेंटर Street-15, sector -5, Civic Centre",
    "भिलाई, दुर्ग, भिलाई, छत्तीसगढ़, Bhilai, Durg. Bhilai, Chhattisgarh,",
]

My code so far:

import re
regex = re.compile("[^a-zA-Z0-9!@#$&()\\-`.+,/\"]+")
for i in phrases:
    print(regex.sub(' ', i))

My output:

["S/O , .-4 , S/O Ashok Kumar, Block no.-4D.",
  "-15, 5. Street-15, sector -5, Civic Centre",
  ", , , , Bhilai, Durg. Bhilai, Chhattisgarh",]

My desire output

["S/O Ashok Kumar, Block no.-4D.",
 "Street-15, sector -5, Civic Centre",
 "Bhilai, Durg. Bhilai, Chhattisgarh,"]

>Solution :

If I look at your data it seems you could use the following:

import regex as re
lst=["S/O अशोक कुमार, ब्लॉक न.-4डी, S/O Ashok Kumar, Block no.-4D.",
      "स्ट्रीट-15, विभाग 5. सिविक सेंटर Street-15, sector -5, Civic Centre",
      "भिलाई, दुर्ग, भिलाई, छत्तीसगढ़, Bhilai, Durg. Bhilai, Chhattisgarh,",]
for i in lst:
    print(re.sub(r'^.*\p{Devanagari}.+?\b', '', i))

Prints:

S/O Ashok Kumar, Block no.-4D.
Street-15, sector -5, Civic Centre
Bhilai, Durg. Bhilai, Chhattisgarh,

See an online regex demo

• ^ – Start string anchor;
• .*\p{Devanagari} – 0+ (Greedy) characters upto the last Devanagari letter;
• .+?\b – 1+ (Lazy) characters upto the first word-boundary