I have an string like codecodecodecodecode…… I need to find repeated word in that string
I found I way but the regular expression it always return half of repeated part I want just
^(.*)\1+$
at the group(1) I want to see just "code"
>Solution :
If it is greedy, it will first match till the end of the line, and will then backtrack until it can repeat 1 or more times till the end of the string, and for an evenly divided part like this of 4 words, you can capture 2 words and match the same 2 words with the backreference \1
If you have 5 words like codecodecodecodecode as in your example there will be a single group, as the only repetition it can do until the end of the string is 5 repetitions.
The quantifier should be non greedy (and repeat 1+ times to not match an empty string) to match as least as possible characters that can be repeated to the right till the end of the string.
^(.+?)\1+$