How to find the unmatched records where only partial records matches the conditions?

I have a table table_A

ID  EMP
1   9999
1   1
2   9999
2   2
2   3
3   9999
3   9999
3   4
3   4
3   4
4   9999
4   9999
4   9999
5   5
5   6

I want the records where where emp <> 9999 but this case should be satisfied not for all the id. So my expected output will be

id emp
1   1
2   2
2   3
3   4
3   4
3   4

Here records with id 4 and 5 are not present because their distinct emp values are either 9999 only or any other values rather than 9999

I tried but not getting the desired results:

SELECT ID, EMP
FROM table_a
WHERE ID IN (
  SELECT ID
  FROM table_a
  WHERE EMP <> 9999
  GROUP BY ID
  HAVING COUNT(DISTINCT CASE WHEN EMP <> 9999 THEN EMP END) > 0
)
AND EMP <> 9999

>Solution :

You want to show all rows where emp is not 9999 and exists a row for the same id with emp = 9999.

select id, emp
from table_a
where emp <> 9999
and id in (select id from table_a where emp = 9999)
order by id, emp;

(Of course, you can use an EXISTS clause instead of the IN clause, if you like that better.)