How to get a next line after a match using python regex

I’m relatively new to python and writing a code to get to the next line after a python regex match.
I looked into the examples like https://regex101.com/r/dQ0gR6/1 and after match, get next line in a file using python bit could not achieve what i intend to capture.

My text is:

FlowRole  SrcAddr        DstAddr        Proto   SrcPort  DstPort  Key Type Vrf   Dst Vrf  Service Instance Session Id Src Local Dst Local CP Redirect NH type   NH id
I         172.16.10.1    172.18.10.1    ICMP    21       2048     1        2     3        1                8389614    1         0         0           2         1
FlowRole  SrcAddr        DstAddr        Proto   SrcPort  DstPort  Key Type Vrf   Dst Vrf  Service Instance Session Id Src Local Dst Local CP Redirect NH type   NH id
R         172.18.10.1    172.18.10.110  ICMP    21       0        1        3     2        1                8389614    0         1         0           2         1

The code that i used to match is:

FlowRole[^\n]+([\r\n]\w+)    --> I;m able to match the line and the next line word but not the entire line..

need some help here.

I want to match the entire line after the pattern match

i.e., I want to match this these two lines:

I         172.16.10.1    172.18.10.1    ICMP    21       2048     1        2     3        1                8389614    1         0         0           2         1
R         172.18.10.1    172.18.10.110  ICMP    21       0        1        3     2        1                8389614    0         1         0           2         1

>Solution :

You were 90% of the way there, I Just changed the \w+ (which looks for only words characters but skips spaces) to [^\r\n] as you used previously to match the whole line) –

FlowRole[^\n]+[\r\n]([^\r\n]+)

This gives the expected output as per regex101