How to instruct Make to copy the i-th file of a list to the i-th path of another list?

I have two lists, both with N elements:

SRC = a/b/foo  a/b/bar  a/b/moo
DST = a/c/fii  a/c/bir  a/c/mee

Is there a way to set a rule that takes the i-th element of SRC as the prerequisite of the i-th element of DST?

I just need to copy, so what I am thinking of is something like

the_i-th_element_of_DST: the_i-th_element_of_SRC
    cp $< $@

As usual, I would like it not to copy if the destination is updated already.

>Solution :

No, there’s nothing like that built-in. You will have to do some magic.

Here’s an example that might work:

# Create an explicit rule for each destination file
$(DST):
        cp $< $@

# Now create a prerequisite relationship between each DST and SRC
# using a recursive user-defined macro

MAKE_PREREQ = $(eval $(firstword $1): $(firstword $2))\
    $(call MAKE_PREREQ,$(wordlist 2,$(words $1),$1),$(wordlist 2,$(words $2),$2))

$(call MAKE_PREREQ,$(DST),$(SRC))

(note I didn’t test this)

I believe this will fail if any of the filenames in SRC or DST contain commas.