How to get a single result from a basic PHP function

January 8, 2022

Here is a PHP function :

public static function getMap($maps, $class = '')
    {
        global $wpdb;
        
        $html = '<div class="jsDivCenter">';
        if(count($maps)){
            
            foreach ($maps as $key => $value) {
                
                if($value[0] !== '' || $value[1] !== ''){
                    
                $sql = "SELECT id FROM {$wpdb->joomsport_maps} WHERE id=".intval($key);
                if($wpdb->get_var($sql)){
                    if(JoomsportSettings::get('partdisplay_awayfirst',0) == 1){
                        $home_map = $value[1];
                        $away_map = $value[0];
                    }else{
                        $home_map = $value[0];
                        $away_map = $value[1];
                    }
                    $html .= '<div class="jsScoreDivMap '.$class.'">'.$home_map.JSCONF_SCORE_SEPARATOR.$away_map.'</div>';
            
                }
                }
            }
        }
        

        $html .= '</div>';

        return $html;

Here is the PHP code :

<?php
        
        if ($rows->lists['maps'] && count($rows->lists['maps'])) {
            echo "<center><font color='blue'>Maps</font></center>";
            echo jsHelper::getMap($rows->lists['maps']);
        }
        ?>

I would like this PHP code to display only the "map" with ID = 4 and not the entire list. How to do this ?

Thanks.

>Solution :

try this code:

<?php
        
        if ($rows->lists['maps'] && count($rows->lists['maps'])) {
            echo "<center><font color='blue'>Maps</font></center>";
            $maparray = $rows->lists['maps'];

            if (!empty($maparray[4])){
                 $newmap[4] = $maparray[4];
                 echo jsHelper::getMap($newmap);
                }
        }
        ?>