How to get a string between two other substrings from a string which includes quotes in python

I have the following string :

name: "gcr.io/myproject/github.com/project/project-1:9246b98256013b49"
digest: "sha256:9a9e3a4fb7072b7"
push_timing {
  start_time {
    seconds: 1660330436
    nanos: 983521156
  }
  end_time {
    seconds: 1660330706
    nanos: 296478248
  }
}

I just want to get the string after ‘name : ‘ and the first following quote ‘"’. The answer string should be ‘gcr.io/myproject/github.com/project/project-1:9246b98256013b49’

I have been trying to use the following command with no luck yet.

image_name = re.search(r'name : "(.*)"', image_info)

So how can I get a string between two other substrings from a string which includes quotes in python ?

>Solution :

It looks like you’re trying to match an extra space in regex.

This line:

image_name = re.search(r'name : "(.*)"', image_info)

is matching for something that starts with name :, while in your file, it starts with name:. Note the extra space.

An easy fix is to just remove the space.

image_name = re.search(r'name: "(.*)"', image_info)

As @KingsMMA mentioned in the comments, your file seems to be in the form of a JSON file. You can try parsing it as such, which means you can retrieve other elements of your file (like digest) much more easily.