Home How to get extract directory name from the full filepath name of a file using glob recursive

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How to get extract directory name from the full filepath name of a file using glob recursive

July 23, 2023

I have two folders cats and dogs with 5 jpeg images in each
cat1.jpeg cat2.jpeg….. dog1.jpeg dog2.jpeg etc…

I want to write a CSV file that looks like this

1,./images/trainnew/dogs/dogs2.jpg,dogs
2,./images/trainnew/dogs/dogs1.jpg,dogs
3,./images/trainnew/cats/cats2.jpg,cats
4,./images/trainnew/cats/cats1.jpg,cats

Where entry dogs and cats at then end of each line refers to the name of the folders dogs and cats within the folder trainnew/

using the code below


from glob import glob
import os
count =1
f = open('test7.csv', 'w')
for filename in glob('./images/trainnew/**/*.jpg', recursive=True):    
    f.write(str(count) + ',' + filename + ',\n')
    print(filename) 
    count +=1

===================

My test7.csv looks like this

1,./images/trainnew/dogs/dogs2.jpg,
2,./images/trainnew/dogs/dogs1.jpg,
3,./images/trainnew/cats/cats2.jpg,
4,./images/trainnew/cats/cats1.jpg,

How do i get the respective directory names and print at the end of each of these lines respectively in the csv file.

>Solution :

from glob import glob
import os

count = 1
with open('test7.csv', 'w') as f:
    for filename in glob('./images/trainnew/**/*.jpg', recursive=True):  
        dirname = os.path.dirname(filename)  # Get the directory name of the file
        foldername = os.path.basename(dirname)  # Get the base name from that directory path
        f.write(str(count) + ',' + filename + ',' + foldername + '\n')
        print(filename)
        count +=1

The os.path.dirname(filename) line retrieves the directory of the current file (like ‘./images/trainnew/dogs’ or ‘./images/trainnew/cats’), and os.path.basename(dirname) give u the base name of that path (like ‘dogs’ or ‘cats’).