In JavaScript, I want to count the number of times "N" in is in the first, second, third, fourth column. I want each other there values. I want to get the number of occurrences in an array in array, and then get four numbers equal the occurrences.
input:
var set =[
['N', 'N', 'Y', 'N'],
['1', 'N', '2', 'N'],
['N', '1', '4', 'N'],
['2', 'N', 'N', '1']]
output: 3 2 2 2
>Solution :
const set = [
['N', 'N', 'Y', 'N'],
['1', 'N', '2', 'N'],
['N', '1', '4', 'N'],
['2', 'N', 'N', '1'],
];
const countNs = row => row.reduce((acc, curr) => acc + (curr === 'N' ? 1 : 0), 0);
// number of Ns in each row
console.log(set.map(countNs));
const transpose = a => a[0].map((_, c) => a.map(r => r[c]));
// Number of Ns in each column
console.log(transpose(set).map(countNs));