How to get rows of Pandas Dataframe where the column value starts with any of given characters

I have the following Pandas Dataframe:

d = {'col1': ["aaa", "bbb", "ccc", "ddd", "acc", "bcc"]}
df = pd.DataFrame(data=d)
df

Output of the above code:

    col1
0   aaa
1   bbb
2   ccc
3   ddd
4   abb
5   bcc

I need to get the rows where the column value starts with – say – either "a" or "c". After the filtering, the result should look as the following:

    col1
0   aaa
1   ccc
2   abb

How can I achieve this without using a for loop?

>Solution :

Just for a and c

df = df[df["col1"].str.match('^[ac].+')]

You can include as many letters in the square brackets that you need to match on.

df = df[df["col1"].str.match('^[abcdefg].+')]