How to get the time of tomorrow 1:30 AM?

I’m using the following expression to get the time of 1:30 AM tomorrow.

import datetime

t = datetime.date.today()
datetime.datetime.combine(t, datetime.time.min) + datetime.timedelta(hours=1, days=1, minutes=30)

Is there a better way to do it?

>Solution :

Your way of writing is totally alright, another way of achieving same task is:

Try it online!

from datetime import datetime
now = datetime.now()
print(datetime(year = now.year, month = now.month,
    day = now.day + 1, hour = 1, minute = 30))

Output:

2021-11-28 01:30:00

Just figured out that the way of writing as above will not work for the last day of the month, then it is better to do as following:

Try it online!

import datetime
now = datetime.datetime.now()
print(datetime.datetime(year = now.year, month = now.month, day = now.day)
    + datetime.timedelta(days = 1, hours = 1, minutes = 30))

Output:

2021-11-28 01:30:00