How to have input in Python only take in string and not number or anything else only letters

I am a beginner in Python so kindly do not use complex or advanced code.

contact = {}

def display_contact():
    for name, number in sorted((k,v) for k, v in contact.items()):
        print(f'Name: {name}, Number: {number}')



#def display_contact():
# print("Name\t\tContact Number")
# for key in contact:
#    print("{}\t\t{}".format(key,contact.get(key)))

while True:
  choice = int(input(" 1. Add new contact \n 2. Search contact \n 3. Display contact\n 4. Edit contact \n 5. Delete contact \n 6. Print \n 7. Exit \n Enter "))
  
#I have already tried


  if choice == 1:
    while True:
      try:
        name = str(input("Enter the contact name "))
        if name != str:
      except ValueError:
        continue
      else:
        break

    while True:
      try:
        phone = int(input("Enter number "))
      except ValueError:
        print("Sorry you can only enter a phone number")
        continue
      else:
        break
    contact[name] = phone
    
  elif choice == 2:
    search_name = input("Enter contact name ")
    if search_name in contact:
      print(search_name, "'s contact number is ", contact[search_name])
    else: 
      print("Name is not found in contact book")
      
  elif choice == 3:
    if not contact:
      print("Empty Phonebook")
    else: 
      display_contact()
      
  elif choice == 4:
    edit_contact = input("Enter the contact to be edited ")
    if edit_contact in contact:
      phone = input("Enter number")
      contact[edit_contact]=phone
      print("Contact Updated")
      display_contact()
    else:
      print("Name is not found in contact book")
      
  elif choice == 5:
    del_contact = input("Enter the contact to be deleted ")
    if del_contact in contact:
      confirm = input("Do you want to delete this contact Yes or No? ")
      if confirm == 'Yes' or confirm == 'yes':
        contact.pop(del_contact)
      display_contact
    else:
      print("Name is not found in phone book")



  elif choice == 6:
    sort_contact = input("Enter yes to print your contact")
    if sort_contact in contact:
      confirm = input("Do you want to print your contact Yes or No? ")
      if confirm == 'Yes' or confirm == 'yes':
        strs = [display_contact]
        print(sorted(strs))     
    else:
      print("Phone book is printed.")
  else:
        break

I tried but keep getting errors and I can’t fiugre out how to make it only take string or letter as input and not numbers.

if choice == 1:
    while True:
      try:
        name = str(input("Enter the contact name "))
        if name != str:
      except ValueError:
        continue
      else:
        break

it is not working my code still accepts the ans in integer and string.

I am a beginner so I might have made a lot of mistakes. Your patience would be appreciated.

>Solution :

You can use a regex with re.fullmatch:

import re

while True:
    name = input("Enter the contact name ")
    if re.fullmatch(r'[a-zA-Z]+', name):
        break

Or use the case-insensitive flag: re.fullmatch(r'[a-z]+', name, flags=re.I):