How to loop menu choice validation in python?

August 17, 2022

I am trying to make a loop to validate my menu choices to be integers, but receiving this error when inputting lettersline 138, in <module> option = int(input("Enter your option:")) ValueError: invalid literal for int() with base 10: 'test' . Sorry if code is a mess only been doing python for 2 weeks approx so still learning.
Ideally I would like the validation to also limit the choice to the 1-6 range for the choices.
P.S. I know it’s wrong, but I just don’t know what.
This is my code:

    print('=============================')
    print('= Inventory Management Menu =')
    print('=============================')
    print('(1) Add New Item to Inventory')
    print('(2) Remove Item from Inventory')
    print('(3) Update Inventory')
    print('(4) Display Inventory')
    print('(5) Search for Item')
    print('(6) Quit')

#Selecting menu option
menu()
option = int(input("Enter your option:"))
while option !=0:
    if option == 1:
        addInventory()
    elif option == 2:
        removeInventory()
    elif option == 3:
        updateInventory()
    elif option == 4:
        printInventory()
    elif option == 5:
        searchItem()
    elif option == 6:
        answer = input("Are you sure you want to quit? Y/N: ")
        if answer == 'Y':
            exit()
        else:
            menu()
            option = (input("Enter your option:"))
    else:
        if option.isdigit():
            pass
        else:
            print("Enter a valid option: ")
    menu()
    option = int(input("Enter your option:"))

>Solution :

Try this:

option = input("Enter your option:")

while not option.isdigit():
   option = input("Enter a valid option:")

option = int(option)

Also you can check if the number is in a certain range:

option = input("Enter your option:")

while not option.isdigit() or int(option) < 1 or int(option) > 6:
    option = input("Enter a valid option:")

option = int(option)