How to loop through all nested dictionary to give all the parent key concatenated and its value

dictionary={' items': { 'heading': 'Maps','description':'Maps123','imagepath':/music/images/','config':{'config1':12,'config2':123}},'db':{'username':'xyz','password':'xyz'},'version':'v1'}

I want the output in the format:

items/heading: Maps

items/description: Maps123

items/image_path: /music/images/v2/web_api-music.png

items/config/config1: abcd

items/config/config2: hello

db/username: xyz

db/password: xyz

version: v1

>Solution :

Check it :

def flatten(x, parent=''):
    for key in list(x.keys()):
        if( type(x[key]) is dict ):
            flatten(x[key], parent+'/'+str(key))
        else:
            print(parent+'/'+str(key)+': ' + str(x[key]))

dictionary={'items': { 'heading': 'Maps','description':'Maps123','imagepath':'/music/images/','config':{'config1':12,'config2':123}},'db':{'username':'xyz','password':'xyz'},'version':'v1'}

flatten(dictionary)