I have a dataframe, which contains many urls, is there a way i can make whenever it finds a specific url "https://abs.twimg.com/sticky/default_profile_images/default_profile_normal.png" it gives a value False, else true?
![https://abs.twimg.com/sticky/default_profile_images/default_profile_normal.png"](https://abs.twimg.com/sticky/default_profile_images/default_profile_normal.png"){kind=link}
My dataframe:
Expected:
| surname | value |
|---|---|
| First | True |
| Second | False |
| Third | True |
| Fourth | False |
>Solution :
You can use contains which creates a boolean mask. By assigning it to df['value'] you assign it to a new column, which gives you the desired result. This is even easier than creating a lambda function for it.
df['value'] = df.image_url.str.contains("https://abs.twimg.com/sticky/default_profile_images/default_profile_normal.png")