How to not print out number 23 in my code?

December 23, 2022

Create a program that takes an array of integers as arguments. The program should output odd numbers from the array and will stop if it encounters the number 23.

import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        int n = in.nextInt();
        int arr[] = new int[n];
        boolean add =true;
        gig(n, arr);
    }

    public static void gig(int n, int arr[]){
        Scanner in = new Scanner(System.in);
        for(int i=0; i<arr.length; i++){
            arr[i] = in.nextInt();
            if(arr[i]%2!=0){
                System.out.println(arr[i]);
            }
            if(arr[i]==23)
                break;
        }        
    }
}

>Solution :

You can change the if conditions order, this way the for loop will break when the number is equal to 23 before it gets printed

import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        int n = in.nextInt();
        int arr[] = new int[n];
        boolean add =true;
        gig(n, arr);
    }

    public static void gig(int n, int arr[]){
        Scanner in = new Scanner(System.in);
        for(int i=0; i<arr.length; i++){
            arr[i] = in.nextInt();
            
            if(arr[i]==23)
              break;
                
            if(arr[i]%2!=0){
                System.out.println(arr[i]);
            }
        }        
    }
}