How to print following pattern getting issue with spaces?

December 23, 2021

I am trying to write the code but not getting how to achieve expected output
Causing issue with space and not able to make proper judgement how to get exact spaces after every iteration

My code :

n=15
cnt=0
lst=[str(' ') for x in range(1,n+1)]
initial_length=len(''.join(lst))
print(initial_length)
for row in range(1,n+1):
  lst[cnt-1]=str(row)
  cnt=cnt-1
  print(' '.join(lst))

Output of above code is not as expected output

                            1
                          2 1
                        3 2 1
                      4 3 2 1
                    5 4 3 2 1
                  6 5 4 3 2 1
                7 6 5 4 3 2 1
              8 7 6 5 4 3 2 1
            9 8 7 6 5 4 3 2 1
          10 9 8 7 6 5 4 3 2 1
        11 10 9 8 7 6 5 4 3 2 1
      12 11 10 9 8 7 6 5 4 3 2 1
    13 12 11 10 9 8 7 6 5 4 3 2 1
  14 13 12 11 10 9 8 7 6 5 4 3 2 1
15 14 13 12 11 10 9 8 7 6 5 4 3 2 1

Expected output :

                                  1
                                2 1                                                                 
                              3 2 1                                                              
                            4 3 2 1
                          5 4 3 2 1                         
                        6 5 4 3 2 1                       
                      7 6 5 4 3 2 1                     
                    8 7 6 5 4 3 2 1 
                  9 8 7 6 5 4 3 2 1
               10 9 8 7 6 5 4 3 2 1 
            11 10 9 8 7 6 5 4 3 2 1 
         12 11 10 9 8 7 6 5 4 3 2 1
      13 12 11 10 9 8 7 6 5 4 3 2 1
   14 13 12 11 10 9 8 7 6 5 4 3 2 1
15 14 13 12 11 10 9 8 7 6 5 4 3 2 1

>Solution :

You have to account for larger digits taking up more space, which means that when creating the list that contains spaces, you need to multiply the space by how many digits are in that number which you can get by len(str(number)):

n = 15

# create a list that contains spaces of length of how many digits
# will be put there, then reverse it because ascending order and convert
# to list
lst = list(reversed([' ' * len(str(x)) for x in range(1, n + 1)]))

# go over each number
for x in range(1, n + 1):
    # create a copy of the list
    c = lst.copy()
    # create a reversed object containing all the numbers
    # up until x
    numbers = reversed([str(x) for x in range(1, x + 1)])
    # replace the last items in list's copy with the reversed order
    # so basically put the numbers at the end
    c[-x:] = numbers
    # join by space and print
    print(' '.join(c))

Also:
I strongly suggest following PEP 8 – Style Guide for Python Code. Function and variable names should be in snake_case, class names in CapitalCase. Don’t have space around = if it is used as a part of keyword argument (func(arg='value')) but have space around = if it is used for assigning a value (variable = 'some value'). Have space around operators (+-/ etc.: value = x + y(except here value += x + y)). Have two blank lines around function and class declarations. Object method definitions have one blank line around them.