How to put a function as an argument with unspecified sub arguments in C?

I am trying to make a function, which will execute a function with the provided sub arguments in C. Like:

int function(void (*func)(), ...) // add as many arguments you want for 'func()'
{
    va_list ptr;

    ...

    func(sub_arguments) // the '...'
}

void *abc(int a) { ... }
void *one(int b, int c) { ... }

int main()
{
   function(abc, 73);
   function(one, 9, 84);
}

Now, is there a way to somehow make a variable list and add it as the arguments and execute it? If so, how?

I know I phrased the question in a very difficult way, but I just don’t get how to do this.

>Solution :

You can either extract each argument in function() and make the relevant call:

#include <stdio.h>
#include <stdarg.h>

void abc(int a) {
    printf("abc(%d)\n", a);
}

void one(int b, int c) {
    printf("one(%d,%d)\n", b, c);
}

int function(void (*func)(), ...) {
    va_list ap;
    va_start(ap, func);
    if(func == abc) {
        int a = va_arg(ap, int);
        func(a);
    } else if(func == one) {
        int b = va_arg(ap, int);
        int c = va_arg(ap, int);
        func(b, c);
    }
    va_end(ap);
    return 0;
}

int main() {
    function(abc, 73);
    function(one, 9, 84);
}

Or change your sub-functions to take a va_list, then pass it from function to the sub-function. That is probably the approach I would would take. If want to call your sub-functions directly that write a wrapper for each that accepts a … argument (like printf() and vpritnf() pair). Note that this requires the sub-functions to have a fixed argument like function() has func.