How to put correct attribute '@id' value based on the '@rid' value

July 28, 2023

I’m trying to put correct value in the attribute @id based on the @rid attribute value.
Logic: If element a more then 1 and element cu equal to 1 in the ‘au’ element than how to add position after the attribute value e.g (<a id="a">...</a>, <a id="a">...</a>) s/b (<a id="a1">...</a>, <a id="a2">...</a>)
How to solve this issue template match only a element.
Please check Expecting Output:

Input:

<root>
<t>Title</t>
<au>
    <cu>
        <x rid="a1 a2"/>
    </cu>
</au>
<a id="a">Centre</a>
<a id="a">Westmead</a>
<n>notes</n>
</root>

XSLT Code:

<xsl:template match="@*|node()">
    <xsl:copy>
        <xsl:apply-templates select="@*|node()"/>
    </xsl:copy>
</xsl:template>

<xsl:template match="a">
    <xsl:if test="count(../a) &gt; 1 and count(../au/cu[x]) = 1 and @id">
        <xsl:for-each-group select="self::node()" group-adjacent="self::a">
                <xsl:variable name="pos" select="position()"/>
                <xsl:element name="a">
                    <xsl:attribute name="id">
                        <xsl:value-of select="concat('a',$pos)"/>
                    </xsl:attribute>
                    <xsl:apply-templates/>
                </xsl:element>
            <!--</xsl:for-each>-->
        </xsl:for-each-group>
    </xsl:if>
</xsl:template>

Expecting Output:

<root>
<t>Title</t>
<au>
    <cu>
        <x rid="a1 a2"/>
    </cu>
</au>
<a id="a1">Centre</a>
<a id="a2">Westmead</a>
<n>notes</n>

>Solution :

If you want to do it from the template for a use

  <xsl:template match="root[a[2] and not(au/cu[x][2])]/a[@id]">
    <xsl:copy>
      <xsl:attribute name="id">a<xsl:number/></xsl:attribute>
      <xsl:apply-templates/>
    </xsl:copy>
  </xsl:template>