How to return a Pointer-To-Array from a function in C?

Pointers-to-array (not array pointers) are a lesser-known feature of the C programming language.

int arr[] = { 3, 5, 6, 7, 9 };
int (*arr_ptr)[5] = &arr;

printf("[2]=%d", (*arr_ptr)[2]);

They allow you to "un-decay" a dynamically allocated array pointer.
(which is pretty cool in my opinion)

int *ptr = malloc(sizeof(int) * 5);
int(*arr_ptr)[5] = (int(*)[5])ptr;

printf("[2]=%d", (*arr_ptr)[2]);

I’m trying to define a function to return an array pointer, without success.
I tried something like this:

int (*)[5] create_arr_5(void) 
{
    int(*arr_ptr)[5] = malloc(sizeof(int) * 5);
    return arr_ptr;
}

>Solution :

The function should be defined like this:

int (*create_arr_5(void))[5]
{
    int(*arr_ptr)[5] = malloc(sizeof(int) * 5);
    return arr_ptr;
}

Talking through the declaration, create_arr_5 is a function:

create_arr_5()

That takes no parameters:

create_arr_5(void)

And return a pointer:

*create_arr_5(void)

To an array of size 5:

(*create_arr_5(void))[5]

Of int:

int (*create_arr_5(void))[5]