How to select all available indices in a dataframe column in Python

I have a dataframe df of multiple variables, with a number of irregularly indexed entries.

Let’s say like this:

        X  Y  
0    60.0  0   
1    63.0  10      
4    80.0  10             
5    46.0  1            
9    73.0  10

[5 rows x 2 columns]

Now, say that I have a list of externally provided indices, indices, like:

indices = [0, 2, 4, 6, 9, 11]

How can I select all entries of df['X'] which are part of the indices? My desired output is

        X  
0    60.0          
4    80.0                          
9    73.0 

If I merely try to call df['X'][indices], Python rightfully complains:

KeyError: '[2, 6, 11] not in index'

Is there a simple way to do this?

>Solution :

Use Index.isin():

print(df.loc[df.index.isin(indices), 'X'])

0    60.0
4    80.0
9    73.0
Name: X, dtype: float64