I am learning python, according to the logic written in the code in the book, I want to see the running result, the code is as follows, but the output error NameError: name 'pr' is not defined
code show as below:
stack=[]
def pushit():
stack:append(input(' Enter New String: ').strip())
def popit():
if len(stack)==0:
print('Cannot pop from an empty stack!')
else:
print ('Removes [','stack.pop()',']')
def viewstack():
print(stack)
CMDs={'u':pushit,'o':popit,'v':viewstack}
def showmenu():
pr='''
p(U)sh
p(O)p
(V)iew
(Q)uit
Enter choice:'''
while True:
while True:
try:
choice=input(pr).strip()[0].lower()
except (EOFError,KeyboardInterrupt,IndexError):
choice='q'
print('\nYou picked:[%s]'%choice)
if choice not in 'uovq':
print('Invalid option,try again')
else:
break
if choice=='q':
break
CMDs[choice]()
if _name_=='_main_':
showmenu()
The error message is as follows:
Traceback (most recent call last):
File "/Users/oliver/Desktop/test.py", line 22, in <module>
choice=input(pr).strip()[0].lower()
NameError: name 'pr' is not defined
>Solution :
There are two errors in your code,
- The logic in the
showmenumethod needs to be indented _name_=='_main_'->__name__ == "__main__"
stack=[]
def pushit():
stack:append(input(' Enter New String: ').strip())
def popit():
if len(stack)==0:
print('Cannot pop from an empty stack!')
else:
print ('Removes [','stack.pop()',']')
def viewstack():
print(stack)
CMDs={'u':pushit,'o':popit,'v':viewstack}
def showmenu():
pr='''
p(U)sh
p(O)p
(V)iew
(Q)uit
Enter choice:'''
while True:
while True:
try:
choice=input(pr).strip()[0].lower()
except (EOFError,KeyboardInterrupt,IndexError):
choice='q'
print('\nYou picked:[%s]'%choice)
if choice not in 'uovq':
print('Invalid option,try again')
else:
break
if choice=='q':
break
CMDs[choice]()
if __name__ == "__main__":
showmenu()