How to sort output result of python code?

I have this code and try to sort the output print result

# -*- coding: utf-8 -*-

from os import path as os_path, listdir as os_listdir


GETPath = os_path.join('/home/usr/Desktop/fonts')

fonts = []
for fontName in os_listdir(GETPath):
    fontNamePath = os_path.join(GETPath, fontName)
    if fontName.endswith('.ttf') or fontName.endswith('.otf'):
        fontName = fontName[:-4]
        fonts.append((sorted(fontNamePath), sorted(fontName)))

But I can not get the sort lines I have got this result

nmsbd
/home/usr/Desktop/fonts/nmsbd.ttf
font_default
/home/usr/Desktop/fonts/font_default.otf
best_font1
/home/usr/Desktop/fonts/best_font1.ttf
NotoNaskhArabic
/home/usr/Desktop/fonts/NotoNaskhArabic.ttf
best_font2
/home/usr/Desktop/fonts/best_font2.ttf
arabic_k
/home/usr/Desktop/fonts/arabic_k.ttf
arabic_beirut
/home/usr/Desktop/fonts/arabic_beirut.ttf
NotoSansArabic
/home/usr/Desktop/fonts/NotoSansArabic.ttf
ae_almateen
/home/usr/Desktop/fonts/ae_almateen.ttf

How to solve this code ?!

>Solution :

First create a list of tuples [(fontPath, fontName), ...] and afterwards sort them by the name:

GETPath = os_path.join('/home/usr/Desktop/fonts')

fonts = []
for fontName in os_listdir(GETPath):
    fontNamePath = os_path.join(GETPath, fontName)
    if fontName.endswith('.ttf') or fontName.endswith('.otf'):
        fontName = fontName[:-4]
        fonts.append((fontNamePath, fontName))
fonts = sorted(fonts, key=lambda x: x[1])