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How to write a simple python program that prints letters in ascending order?

byMR

November 22, 2022

For example I would like to have:

.
.
.

aaa

and so on.

Currently I’m here but I am lost. So feel free to propose a completely different solution.

count = 0
string = ''
for i in range(100):
    count += 1
    if i % 26 == 0:
        count = 0
        string += 'a'
    ch = 'a'
    x = chr(ord(ch) + count)
    string = string[:-1] + x
    print(i + 1, string)

and my output is something like this:

1 a

2 b

.
.
.

26 z

27 za

28 zb

.
.
.

52 zz

53 zza

54 zzb

.
.
.

>Solution :

Maybe try something like the following:

range(97,123) simply creates a range of numbers from 97 to 122, which converted to ASCII equates to a…z (done using chr())

So all our FUnction does, is it recieves a base string (starts with empty), prints out the base + range of charachters and calls its self with base + every charachter as the new base and depth decremented by 1

def printcharachters(base, depth):
    if depth > 0:
        for a in range(97, 123):
            print(base + chr(a))

        for a in range(97, 123):
            printcharachters(base + chr(a), depth - 1)



printcharachters("", 2)

Replace the depth with your desired depth (for 2 the last string would be zz for 4 it would be zzzz).