How would I get the results from this to end at a value of 2?

February 1, 2022

This is a countdown calculator that shows all even numbers from user input to 2. If the user inputs an odd number, it adds 1 to make the number even. I need it to stop at 2, but I’m not sure how.

startVal = int(input("Enter a starting value:"))
loss = 2
if startVal % 2 == 1:
    startVal = startVal + 1
    for i in range(2, startVal + 1):
        startVal -= loss
        print(startVal)

>Solution :

all code inside a loop will execute will execute the number of times you specify in the loop condition

> for i in range (0,6):
      print("Hello")

would print the word ‘Hello’ 5 times. Please read on the concept of loops.
Meanwhile here is a working solution. (given the input is odd). Use this to figure out how you would do the same logic for an even number.

startVal=int(input("Enter a starting value:"))
loss=2
if startVal%2==1:
    startVal=startVal+1
    temp  = int((startVal/2) - 1)
    for i in range(0,temp):
     startVal-=loss
     print(startVal)

Enter a starting value:17