I have a problrm with if statement and while loop and dictionary in python

February 7, 2022

men = {1111111111: 'Amal', 2222222222: 'Mohammed', 3333333333: 'Khadijah', 4444444444: 'Abdullah', 5555555555: 'Rawan',
       6666666666: 'Faisal', 7777777777: 'Layla'}


def mo():
    r = int(input('Please Enter The Number: '))
    if r in men:
        print(men[r])
    elif r not in men:
        print('Sorry, the number is not found')
    elif r >= 11:
        while r >= 11:
            r = r + 1 == 1
            print('This is invalid number')
mo()

I have problem in the elif. What I want is if I write more than 10 characters in the console, then the code will print 'This is invalid number'. But instead the code prints 'Sorry, the number is not found'.

Output:

Please Enter The Number: 111111111111111
Sorry, the number is not found

Process finished with exit code 0

>Solution :

The answer posted by ksohan is correct, but there’s a catch. What you want is if the number entered is greater than 10 characters, then console will print ‘This is invalid number’. If you want to compare the length of characters then you should first typecast r variable to string and then compare its length with 10.

Try this:

men = {1111111111: 'Amal', 2222222222: 'Mohammed', 3333333333: 'Khadijah', 4444444444: 'Abdullah', 5555555555: 'Rawan',
       6666666666: 'Faisal', 7777777777: 'Layla'}


def mo():
    r = int(input('Please Enter The Number: '))
    if r in men:
        print(men[r])
    elif len(str(r)) > 10:
        print('This is invalid number')
    elif r not in men:
        print('Sorry, the number is not found')
mo()