So i have problem with multiplication by 0.[closed]
This is my program:
#include <stdio.h>
int main() {
int i,c,x,b,q,w,e,r,t,y,u;
for (i = 1; i <=11; i++) {
printf("0 * %-2d = %-2d\n", i - 1, x=0), x = x * 0;
}
for (i = 1; i <= 11; i++)
{
printf("1 * %-2d = %-2d\n",i-1,x),x= 1 * i;
}
for (i = 1; i <= 11; i++)
{
printf("2 * %-2d = %-2d\n",i-1,b),b= 2 * i;
}
for (i = 1; i <= 11; i++)
{
printf("3 * %-2d = %-2d\n",i-1,c),c= 3 * i;
}
for (int i = 1; i <= 11; i++)
{
printf("4 * %-2d = %-2d\n",i-1,q),q= 4 *i;
}
for (int i = 1; i <= 11; i++)
{
printf("5 * %-2d = %-2d\n",i-1,w),w= 5 *i;
}
for (int i = 1; i <= 11; i++)
{
printf("6 * %-2d = %-2d\n",i-1,e),e= 6 *i;
}
for (int i = 1; i <= 11; i++)
{
printf("7 * %-2d = %-2d\n",i-1,r),r= 7 *i;
}
for (int i = 1; i <= 11; i++)
{
printf("8 * %-2d = %-2d\n",i-1,t),t= 8 *i;
}
for (int i = 1; i <= 11; i++)
{
printf("9 * %-2d = %-2d\n",i-1,y),y= 9 *i;
}
for (int i = 1; i <= 11; i++)
{
printf("10 * %-2d = %-2d\n",i-1,u),u= 10 *i;
}
return 0;
}
And i have problem with output by 0
- 10 * 0 = 32599
- 10 * 1 = 10
- 10 * 2 = 20
- All good with multiplication by 1,2,3… but with zero i have problem and don’t know what to do
>Solution :
Regarding @kaylum’s comment about using a nested for loop, it looks like you’re really just looking for something like this…
#include <stdio.h>
int main() {
for (int x = 0; x <= 10; x++) {
for (int y = 1; y <= 10; y++) {
printf("%-2d * %-2d = %-2d\n", x, y, x * y);
}
}
return 0;
}