Identifying the identical elements in two arrays with same location(index)

November 28, 2022

Ok, so I want to return the elements that are present in both provided arrays having the same index location.

exe1 = [A,B,C,D,N]
exe2 = [B,D,C,A,T]

it should return only C

I’ve tried looping them by nested loops but doesn’t work, here is what I’ve tried:

 let testing = []
       for (let i = 0; i < exe1.length; i++){
         for(let j = 0; j < exe2.length; j++){
           if(exe1[i] === exe2[j]){
             testing.push(exe1[i])
           }
         }
       };
       return testing;

mind the names of the arrays, please

>Solution :

You can use a simple filter to only include values in exe1 that have the same value at the same index of exe2.

const exe1 = ['A','B','C','D','N'];
const exe2 = ['B','D','C','A','T'];

const testing = exe1.filter((val, i) => val === exe2[i]);

console.log(testing)