If python don't have tail recurssion in it, then why my code on leetcode is working differently for diffirent recursions?

As per the link tail recursion is not present in python. I was working on leetcode problem where two inputs are given, number and its power. The power can be negative also. I need to find out exponent using recursion.

This was my code which was not getting accepted:

class Solution(object):
    def myPow(self, x, n):
        """
        :type x: float
        :type n: int
        :rtype: float
        """
        def po(x,n):
            if n ==1:
                return x
            if n== 2:
                return x * x

            if n % 2==0:
                return po(x * x, n//2)
            else:
                return x * po(x * x,(n-1)//2)
        
        p = po(x,abs(n))

        if n < 0:
            return float(1)/p
        else:
            return p

For the above code I received error:

RuntimeError: maximum recursion depth exceeded
    return po(x * x, n//2)
Line 15 in po (Solution.py)
    return po(x * x, n//2)
Line 15 in po (Solution.py)
.
.
.
.

But for this code, it worked properly:

class Solution(object):
    def myPow(self, x, n):
        """
        :type x: float
        :type n: int
        :rtype: float
        """
        def po(x,n):
            if n ==0:
                return 1
            if n < 0:
                return 1.0/po(x,-1*n)

            if n % 2==0:
                return po(x * x, n//2)
            else:
                return x * po(x * x,(n-1) // 2)
        
        return po(x,n)

>Solution :

Tail recursion isn’t the issue.

In the original code, if n is 0, it will just keep recursing without end, until it reaches the maximum recursion limit. It goes past the checks for 1 and 2, and then, since 0 is even, it does return po(x * x, n//2). Since n//2 is also 0, it never ends. You just need to add a check for n equal to 0.