In Python, split a file into lines, and then print only ones starting with

So, I have a file, for example, ‘test.txt’. I want to check and print only the lines starting with ‘result’:

test.txt looks like this:

this is a test file
used to test a python script
result 1
dummy text goes here
result is nice
blah blah blah
the end

Then, what i want is for the print only output like this:

result 1
result is nice

I’m having difficulties trying to figure this one out, because apparently i can’t use startswith() function, since when i split the file it becomes a list, here’s the code I last tried:

with open('test.txt', 'r') as text:
     lines=text.readlines()
     for x in lines:
          if lines[x].startswith('result'):
               print(lines[x])

And that gets me the error message:

Traceback (most recent call last):   
File "test.py", line 10, in <module>
if lines[x].startswith('result'):
TypeError: list indices must be integers or slices, not str

What can I do instead? Thanks in advance.

>Solution :

In the loop you created, all the lines are already assigned to the lines list, and you assign them to the variable x sequentially with the loop. That’s why you can access it directly using x when accessing it inside the loop.

with open('test.txt', 'r') as text:
    lines = text.readlines()
    for x in lines:
        if x.startswith('result'):
            print(x)