In what ways do we get out of if/else condition? java

I did this code:

private static void fix (List<String> hg){

        String k1 = hg.get(0);
        String k2 = hg.get(1);
        String k3 = hg.get(2);
        String k4 = hg.get(3);
        String k5 = hg.get(4);

        List <Character> d = new ArrayList<>();

            for (int j = 0; j < k1.length(); j++) {
                d.add(j, k1.charAt(j));
            }

Iterator <Character> sdf = d.iterator();
while (sdf.hasNext()){
  Character r = sdf.next();
  if (r.equals('g')){
    hg.add(k1);
  }
  if (r.equals('d')){
    hg.remove(k1);
  }
  if (r.equals('g') || r.equals('d')){ }// how to get out of this "if" beyond what I did?

}

The main idea is to ignore words containing letters ‘g’ and ‘d’.

I know that we can use such methods like:

1. if (r.equals('g') || r.equals('d')){ continue; }
2. if (r.equals('g') || r.equals('d')){ break; }
3. if (r.equals('g') || r.equals('d')){ System.out.println(); }

3 of them are useless, cause idea tells that operator continue is unnecessary as the last statement in a loop. Operator break is not appropriate, cause it literally breaks the code and it won’t work correctly.
System.out.println() fits well, but it makes a huge space in the console.

>Solution :

you should be use else if

Iterator<Character> sdf = d.iterator();
while (sdf.hasNext()) {
    Character r = sdf.next();
    if (r.equals('л')) {
        hg.add(k1);
    } else if (r.equals('р')) {
        hg.remove(k1);
    } else if (r.equals('g') || r.equals('d')) {
       continue;
    }
   
}