Invalid argument in Python

I am trying to create some file paths to create new csv file in the target folder.
My code is as follows.

#The original path.
path_1=r'C:\Users\hh\OneDrive - Technology, Inc\IE'

#Creating the new path with the original path.
folder_name='New Folder'
x='\\'
path_2='r'+"'"+path_1+x+folder_name+"'"

#Creating the other new path with csv file name.
import csv
csv_name='r'+"'"+path_1+x+folder_name+x+'New File.csv'+"'"

#Creating a new csv file in the target folder.
with open(csv_name, 'wb') as csvfile:
    filewriter = csv.writer(csvfile, delimiter=',',
                            quotechar='|', quoting=csv.QUOTE_MINIMAL) 

I had checked the paths I created many times, and didn’t find anything wrong. However, It keeps showing the error as follows.

[Errno 22] Invalid argument: "r'C:\\Users\\hh\\OneDrive - Technology, Inc\\IE\\New Folder\\New File.csv'"

Please help me find out what did I do wrong.

>Solution :

Remove the ‘r’ +
And then, if you want concatenate file path, use os.path.join() like this

import os


folder_name = r"C:/test/today"
name = "test.csv"
print(os.path.join(folder_name, name))  # C:/test/today/test.csv