Is it possible to provide a default value and destructure that value at the same time in Javascript?

Here’s what I mean, I want to do something that is a combination of :

const {b: {c}} = a;

and

const {b={c:0}} = a;

I know I can break them apart like:

const a = {};
const {b={c:0}} = a;
const {c} = b;
console.log(c); //will get 0

But is there anyway to do them in a single statement? Something like (below code doesn’t work):

const a = {};
const{b:{c}={c:0}} = a;
console.log(c); // Hoping to get 0

>Solution :

Assuming you want to get a default c value, you could use a nested default value and destructuring.

const
    getC = a => {
        const { b: { c = 0 } = {} } = a;
        return c;
    };

console.log(getC({}));
console.log(getC({ b: {} }));
console.log(getC({ b: { c: 42 } }));